Asked by Joel
If the temperature of 150.0g of water increased from 23.3C to 44.8C, how much heat was absorbed
Answers
Answered by
Joel
In units of joules. And in units of calories?
Answered by
DrBob222
q = mass H2O x specific heat H2O x delta T.
Use 4.184 J/g for specific heat H2O for q in joules.
Use 1 cal/g for specific heat H2O for q in calories.
OR a quicker way is to calculate calories first and multiply that answer by 4.184 to convert to J.
Use 4.184 J/g for specific heat H2O for q in joules.
Use 1 cal/g for specific heat H2O for q in calories.
OR a quicker way is to calculate calories first and multiply that answer by 4.184 to convert to J.
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