If the temperature of 150.0g of water increased from 23.3C to 44.8C, how much heat was absorbed
2 answers
In units of joules. And in units of calories?
q = mass H2O x specific heat H2O x delta T.
Use 4.184 J/g for specific heat H2O for q in joules.
Use 1 cal/g for specific heat H2O for q in calories.
OR a quicker way is to calculate calories first and multiply that answer by 4.184 to convert to J.
Use 4.184 J/g for specific heat H2O for q in joules.
Use 1 cal/g for specific heat H2O for q in calories.
OR a quicker way is to calculate calories first and multiply that answer by 4.184 to convert to J.
1 answer