Asked by Vinnie

the perimeter of a basketball court is 268 feet. the area is 4200 ft2. find the dimensions. using quadractics
Answered by PsyDAG
2L + 2W = 268

L * W = 4200

W = 4200/L

2L + 2(4200/L) = 268

Solve for L, then W.
Answered by ;&/7:
27262
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