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29.93 g requires 96,485 C.
? g can we obtain from 72,000.
29.93 x (72,000/96,485) =
How many grams of nickel can be produced by passing a current of 15.0A through aqueous nickel(II) chloride for 80.0 minutes?
I'm not sure if I'm on the right path...
All I know is that
1 coloumb= amperes x seconds
1F=96485c/eq
eq=molar mass/charge
Since MM of Ni= 58.69g/mol and the charge is 2, eq= 29.345
If the current is 15A, and it runs for 80 minutes, then 80*60*15=72000C
Where do I go from here?
1 answer
1 answer