Asked by Hana
Ba(OH)2 is a strong electrolyte. Determine the concentration of each of the individual ions in a 0.700 M Ba(OH)2 solution.
I know that
Ba(OH)2 -> Ba + 2OH
But how do I determine the concentrations? I feel like I am making this more complicated than need be
I know that
Ba(OH)2 -> Ba + 2OH
But how do I determine the concentrations? I feel like I am making this more complicated than need be
Answers
Answered by
DrBob222
Yes, you certainly are making it more than it is.
0.700 M Ba(OH)2 means 0.700 mols Ba(OH)2/L soln.
So [Ba(OH)2] = 0.700 M
When it dissociates, according to the equation you wrote, then
(Ba^2+) = 0.700 M
(OH^-) = 2*0.700 M = ? BECAUSE there are twice as many OH^- as Ba^2+. Ba^+ = the same as [Ba(OH)2] BECAUSE one(1) molecule Ba(OH)2 produces one (1) ion of Ba^2+ (and of course two (2) ions of OH^-.
0.700 M Ba(OH)2 means 0.700 mols Ba(OH)2/L soln.
So [Ba(OH)2] = 0.700 M
When it dissociates, according to the equation you wrote, then
(Ba^2+) = 0.700 M
(OH^-) = 2*0.700 M = ? BECAUSE there are twice as many OH^- as Ba^2+. Ba^+ = the same as [Ba(OH)2] BECAUSE one(1) molecule Ba(OH)2 produces one (1) ion of Ba^2+ (and of course two (2) ions of OH^-.
Answered by
Michigan tech
YOu wRonG
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