Asked by thapelo
if sin 41'=m. write m in terms of cos 41'
Answers
Answered by
Reiny
we know
sin^2 41° + cos^2 41° = 1
m^2 = 1 - cos^2 41°
m = ±√(1 - cos^2 41°)
sin^2 41° + cos^2 41° = 1
m^2 = 1 - cos^2 41°
m = ±√(1 - cos^2 41°)
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