in triangle DEF,<D=50 degree, DE=14 meters, and DF=10 meters. find the area of triangle DEFto the nearest tenth of a square meters

Answer 1

If you have a triangle with sides a and b and Ø is the angle between them, then the area is
(1/2)ab sinØ

you have that condition, so
Area = (1/2)(14)(10)sin50° = appr 53.623
or to the nearest tenth ----> 53.6 m^2