Asked by VIVAN
The perimeter of a rectangular field is 182 m, and its area 1938 m2. Find its dimensions.
Answers
Answered by
Steve
the sides are x and 91-x, so
x(91-x) = 1938
x^2-91x+1938=0
(x-34)(x-57) = 0
the field is thus 37x54
x(91-x) = 1938
x^2-91x+1938=0
(x-34)(x-57) = 0
the field is thus 37x54
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