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Asked by melissa

There are 3 reds, 4 blues, 6 whites and 5 yellows in a bag. What is the probability that the first two you draw are both red if you do not replace the first one?
12 years ago

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Answered by Reiny
prob = (3/18)(2/17) = 1/51
12 years ago
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There are 3 reds, 4 blues, 6 whites and 5 yellows in a bag. What is the probability that the first two you draw are both red if you do not replace the first one?

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