Asked by anoynomous
The remainder obtained by dividing
x^2 -3kx +2 by ( x+2) is twice the
remainder obtained by dividing x^2 +3x –k by ( x+3). Find the value of k
x^2 -3kx +2 by ( x+2) is twice the
remainder obtained by dividing x^2 +3x –k by ( x+3). Find the value of k
Answers
Answered by
Steve
so, we need
6k+6 = 2(-k)
k = -3/4
odd answer, but it works.
6k+6 = 2(-k)
k = -3/4
odd answer, but it works.
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