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How many grams of KClO3 must react to form 42.0 mL?

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At STP moles O2 = 0.042 L x 22.4 =0.941

Moles KClO3 = 0.941 x 2/3 =0.627

mass KClO3 = 0.627 mol x 122.55 g/mol=76.8 g
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