Question

Draw and solve any triangles satisfying alpha = 20 degrees
b = 10
c = 16

Answer 1

Using the law of cosines (and assuming alpha is between b and c), then

a^2 = 10^2+16^2-2 * 10*16 * cos 20

a^2 = 356 - 320 * cos 20

Figure out cos 20, we get roughly 0.93969262078

we plug this in to get roughly 55.2983614 for side a.

I don't know what else you mean....