Asked by Lin
Can someone solve this integral for me? My calculator just gives me a decimal approximation but I need an exact number. Thanks! :)
pi[{3ln(3)^2 - 6ln (3) + 6} - {ln(1)^2 - 2 ln(1) + 2}]
pi[{3ln(3)^2 - 6ln (3) + 6} - {ln(1)^2 - 2 ln(1) + 2}]
Answers
Answered by
drwls
That does not look like a function to be integrated. It looks like a number to be calculated. You can start out simplifying it by recognizing that
ln(1) = 0.
When you write ln(3)^2, do you mean
[ln(3)]^2 or ln[3^2]? They are not the same. I will assume the latter.
ln [3^2] = 2 ln 3, so
3 ln[(3)^2] - 6ln (3) = 0
That leaves you with pi (6 - 4) = 2 pi
ln(1) = 0.
When you write ln(3)^2, do you mean
[ln(3)]^2 or ln[3^2]? They are not the same. I will assume the latter.
ln [3^2] = 2 ln 3, so
3 ln[(3)^2] - 6ln (3) = 0
That leaves you with pi (6 - 4) = 2 pi
Answered by
Lin
I'm confused. When I wrote it out by hand, I got:
ð(3ln(9)-6ln(3)+6)-(ln(1)-2ln(1)+2)
ð(ln(93)-ln(36)+6)- 2 (since ln(1)=0)
ð(ln(729)-ln(729)+6)-2
6ð-2
ð(3ln(9)-6ln(3)+6)-(ln(1)-2ln(1)+2)
ð(ln(93)-ln(36)+6)- 2 (since ln(1)=0)
ð(ln(729)-ln(729)+6)-2
6ð-2
Answered by
Lin
the weird symbol is pi
Answered by
Lin
and that 93 is 9^3
Answered by
Lin
and that 36 is 3^6