Asked by Blueberry Tuffin
Find the work done in moving a particle along the quadrant circle that has radius 2, going from A = (2, 0) to B = (0, 2) in the x-y plane through the force field F given by: F = (x - y)i + (x)j
No diagram sorry, but the information provided does allow for a full diagram to be wrought.
I made a start on it by using r = xi + yj and x = cos theta y = sin theta. The answer I got was 4/3i. Is this right? Thanks a lot!! From the blueberry tuffin :)
No diagram sorry, but the information provided does allow for a full diagram to be wrought.
I made a start on it by using r = xi + yj and x = cos theta y = sin theta. The answer I got was 4/3i. Is this right? Thanks a lot!! From the blueberry tuffin :)
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hahaha lol
maths 2a
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