15.67g = mass MgCO3.xH2O
-7.68 g = mass MgCO3
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xxxxx = mass H2O
mols H2O = grams/molar mass
mols MgCO3 = grams/molar mass
Find ratio of 1 mol MgCO3 to x mols H2O. That will be the empirical formula of the hydrate.
A 15.67gsample of hydrate of magnesium carbonate was carefully heated, without decomposing the carbonate to drive off water. The mass was reduce to 7.58g. What is the formula of the hydrated?
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