Yes, you are correct. To find the moles per litre concentration of H2O2 in the solution, you first need to convert the volume and concentration provided for KMnO4 to moles.
First, let's convert the volume of KMnO4 solution given to moles:
Volume of KMnO4 = 46.9 mL
Concentration of KMnO4 = 0.145 mol/L
To convert mL to L, divide the volume by 1000:
46.9 mL = 46.9/1000 = 0.0469 L
Now, we can use the equation C = n/V, where C is the concentration in mol/L, n is the number of moles, and V is the volume in liters.
So, the number of moles of KMnO4 can be calculated as follows:
n(KMnO4) = C(KMnO4) * V(KMnO4) = 0.145 mol/L * 0.0469 L = 0.006813 moles of KMnO4
Now, let's find the number of moles of H2O2 using the stoichiometry of the balanced equation.
From the balanced equation, we can see that the molar ratio between KMnO4 and H2O2 is 2:5.
That means, for every 2 moles of KMnO4, there are 5 moles of H2O2.
Using the molar ratio, we can determine the moles of H2O2:
n(H2O2) = (n(KMnO4) * 5) / 2 = (0.006813 mol * 5) / 2 = 0.01703325 moles of H2O2
Next, we need to find the volume of H2O2 solution used in the titration.
Volume of H2O2 solution = 50.0 mL
Again, convert mL to L:
50.0 mL = 50.0/1000 = 0.0500 L
Finally, we can calculate the concentration of H2O2 in moles per litre (mol/L):
C(H2O2) = n(H2O2) / V(H2O2) = 0.01703325 moles / 0.0500 L = 0.340665 mol/L
Therefore, the moles per litre concentration of H2O2 in the solution is 0.340665 mol/L.