Asked by tom

What is the value of t in the solution to this systems of linear equations?
2s – 3t = –1
3s – 4t = 0

a)–5
b)3
c)-7/3
d)4
Answered by Henry
Multiply both sides of the 1st Eq by -3, and multiply the 2nd Eq by 2. Then add the Eqs.

-6s + 9t = 3
+6s - 8t = 0

t = 3.
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