Asked by Madison
Calculate the mass of 0.0122 moles of: a) Si3N4 b) (CH3)3 N
Answers
Answered by
maggie
a.) 0.0122mol x 140gSi3N4 = 1.708 molSi3N4
b.) 0.0122mol x 59g(CH3)3N =0.7198 mol(CH3)3N
b.) 0.0122mol x 59g(CH3)3N =0.7198 mol(CH3)3N
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