Asked by Jane
Pythagorean Theorem
A rectanglar box is 9 in. wide, 11 in. tall, and 20 in. long. What is the diameter of the smallest circular opening through which the box will fit? If necessary, round to the nearest tenth of a centimeter.
A rectanglar box is 9 in. wide, 11 in. tall, and 20 in. long. What is the diameter of the smallest circular opening through which the box will fit? If necessary, round to the nearest tenth of a centimeter.
Answers
Answered by
Reiny
Try to put it through the circle using the smaller end
that is, the 9 by 11 end
We need the diameter of that rectangle
x^2 = 9^2 + 11^2 = 202
x = √202 = appr 14.2
so the circle will have to be > 14.2
that is, the 9 by 11 end
We need the diameter of that rectangle
x^2 = 9^2 + 11^2 = 202
x = √202 = appr 14.2
so the circle will have to be > 14.2
Answered by
Madison
A rectangular box is 9 cm wide, 9 cm tall, and 5 cm long. What is the diameter of the smallest circular opening through which the box will fit?
Answered by
Anonymous
9,9,6
Answered by
randy
i like this
Answered by
randy
i hate math
Answered by
Sierra's List
this is dumb
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