[radius (perpendicular) * sin35º] / [radius perpendicular*cos 35º]
-the radius cancel and your left with....
sin35º / cos35º
=.70 is the coefficient of static friction
a climber with a weight of 590 N is held by a belay rope connected to her climbing harness and belay device; the force of the rope on her has a line of action through her center of mass. The indicated angles are θ = 35˚ and φ = 35˚. If her feet are on the verge of sliding on the vertical wall, what is the coefficient of static friction between her climbing shoes and the wall?
1 answer