Asked by Katelyn
Verify that each trigometric equation is an identity.
1/1-sinx + 1/1+sinx = 2 sec^2x
1/1-sinx + 1/1+sinx = 2 sec^2x
Answers
Answered by
Reiny
I will assume you mean
1/(1-sinx) + 1/(1+sinx) = 2 sec^2 x
LS = (1 + sinx + 1 - sinx)/((1-sinx)(1+sinx))
= 2/(1-sin^2 x)
= 2/cos^2 x
= 2sec^2 x
= RS
1/(1-sinx) + 1/(1+sinx) = 2 sec^2 x
LS = (1 + sinx + 1 - sinx)/((1-sinx)(1+sinx))
= 2/(1-sin^2 x)
= 2/cos^2 x
= 2sec^2 x
= RS
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