Asked by luz
the height of a triangle is 5 cm more than the length of the base. if the area of a triangle is 133 cm^2 find the hight nad length of the base
Answers
Answered by
Steve
a = bh/2
133 = b(b+5)/2
b(b+5) = 266
b=14, so h=19
133 = b(b+5)/2
b(b+5) = 266
b=14, so h=19
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