Asked by Dillon
Solve an equilibrium problem (using an ICE table) to calculate the of each of the following solutions.
.16M CH3NH3Cl
.16M CH3NH3Cl
Answers
Answered by
DrBob222
Your post is incomplete. You don't specify what you want calculated.
....CH3NH3^+ + H2O ==> H3O^+ + CH3NH2
I....0.16................0........0
C.......-x.............. x........x
E....0.16-x..............x........x
Ka(for CH3NH3Cl) = [Kw/Kb for CH3NH2)] = (x)(x)/(0.16-x) and solve for x = (H3O^+) and convert to pH if needed.
....CH3NH3^+ + H2O ==> H3O^+ + CH3NH2
I....0.16................0........0
C.......-x.............. x........x
E....0.16-x..............x........x
Ka(for CH3NH3Cl) = [Kw/Kb for CH3NH2)] = (x)(x)/(0.16-x) and solve for x = (H3O^+) and convert to pH if needed.
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