Question

In how many ways can the letters of MAHABHARAT be arranged so that
i) B n T are never together
ii) M,A,T n H occurs at first four places

Answer 1

10 letters with 4 A's , 2 H's

a) without any restrictions, number of arrangements
= 10!/(4!2!) = 75600

consider the BT as one element
so we have 9 to arrange, with 4 A's and 2 H's
= 9!/(4!2!) = 7560

number of ways with the BT apart = 75600-7560 = 68040

b) Put the MATH in the front, that leaves
6 letters to arrange, containing of 3 A's
the remaining 6 letters can be arranged in 6!/3! or 120 ways.

That answer assumes that the front MATH stays that way.
If the MATH can be further arranged, but those letters still at the front,
then the number of ways would be 4!x(120) = 2880

Answer 2

The scale of a map is given as 1:2,00000. Two cities are 3 cm apart on the map. Calculate the actual distance between them.

Answer 3

Scale of map = 1:200000
Distance between two cities = 3cms
Consider map scale = 1cm : 200000 cms
200000 cms = 2 Km
3 cms = 3 X 2 kms = 6 kms
Therefore, Actual distance between two cities = 6 kms.