Can someone help check this for me???
I believe the answer is B but I am really unsure....
Q:Sabrina is making two bird feeders in the shape of right rectangular prisms. The smaller feeder has dimensions that are 1/4 of the dimensions of the larger feeder. Using the formula V=lwh, how do their volumes compare???
A:
A) The volume of the larger feeder is 4 times as great as the volume of the smaller feeder.
B) The volume of the larger feeder is 12 times as great as the volume of the smaller feeder.
C) The volume of the larger feeder is 64 times as great as the volume of the smaller feeder.
D) The volume of the larger feeder is 82 times as great as the volume of the smaller feeder.
2 answers
if the sides scale by 4, the volume scales by 4^3=64, so (C)
You can see why this is, since the original volume is
v = lwh
Now, with each dimension scaled by 4,
V = (4l)(4w)(4h) = 4*4*4(lwh) = 4^3 v
You can see why this is, since the original volume is
v = lwh
Now, with each dimension scaled by 4,
V = (4l)(4w)(4h) = 4*4*4(lwh) = 4^3 v
1 answer