Asked by Anonymous

a lab assistant wants to make 5 liters of 27.8% acid solutions. if solutions of 50% and 13% are in stock, how many liters of each must be mixed to prepare the solution?

Answers

Answered by Steve
just work with the amount of acid in each part. If there's x L of 50% acid,

.50x + .13(5-x) = .278(5)
x=2
Answered by jack
yup
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