Asked by JIM
A ball of mass 0.150kg is dropped from a height of 1.25m. It rebounds from the floor to reach a height of 0.960m. What impulse was given to the ball by the floor?
Answers
Answered by
drwls
Calculate the downward velocity V1 when it hits the floor:
V1 = sqrt (2gH), where H = 1.25 m
Then calculate the upward velocity after the bounce:
V2 = sqrt (2gH'), where H' = 0.96 m
The momentum change is M(V1 + V2), since the V's are in opposite directions.
The momentum change equals the impulse given by the floor.
V1 = sqrt (2gH), where H = 1.25 m
Then calculate the upward velocity after the bounce:
V2 = sqrt (2gH'), where H' = 0.96 m
The momentum change is M(V1 + V2), since the V's are in opposite directions.
The momentum change equals the impulse given by the floor.
Answered by
[email protected]
1.35kgm/s
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