Asked by asia
use the seven step method to graph the following rational function:
f(x)=3x^2+x-4/2x^2-5x
a. determine the symmetry of the function.
b. find the x and y intercepts.
c. find the verticle asymptote
d.find the horizontal asymptote
e.plot the points between and beyond the x intercept and verticle asymptote.
I don't get any of this. help me please?
f(x)=3x^2+x-4/2x^2-5x
a. determine the symmetry of the function.
b. find the x and y intercepts.
c. find the verticle asymptote
d.find the horizontal asymptote
e.plot the points between and beyond the x intercept and verticle asymptote.
I don't get any of this. help me please?
Answers
Answered by
Steve
How can you not get <b>any</b> of this?
symmetry may be a bit tough:
f(x) = (3x+4)(x-1) / x(2x-5)
I don't see any symmetry there at all.
the intercepts are easy, right?
Vertical asymptote where denominator si zero
horizontal asymptote is y when x gets huge. There, all the small powers of x become insignificant, and you are working with
3x^2/2x^2 = 3/2
visit wolframalpha.com and enter
(3x^2+x-4)/(2x^2-5x)
for a graph
symmetry may be a bit tough:
f(x) = (3x+4)(x-1) / x(2x-5)
I don't see any symmetry there at all.
the intercepts are easy, right?
Vertical asymptote where denominator si zero
horizontal asymptote is y when x gets huge. There, all the small powers of x become insignificant, and you are working with
3x^2/2x^2 = 3/2
visit wolframalpha.com and enter
(3x^2+x-4)/(2x^2-5x)
for a graph
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