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-(-2)^0*(-2)^3*(-2)^-4/(-2)^3
1 answer
-(-2)^0*(-2)^3*(-2)^-4/(-2)^3
n^0=1 for any n≠0, so
-1*(-2)^3*(-2)^-4/(-2)^3
(-2)^3 = -8 and (-2)^-4 = 1/16, so
-(-8)(16)/(-8)
-1/16
