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Three circles with different radii have their centers on a line. The two smaller circles are inside the largest circle, and each circle is tangent to the other two. The radius of the largest circle is 10 meters. Together the area of the two smaller circles is 68% of the area of the largest circle. Find the product of the radii of the smaller circles.
12 years ago

Answers

Steve
Let the radii of the two smaller circles be x and a0-x

pi x^2 + pi(10-x)^2 = .68 * pi * 10^2
x = 2,8

2*8 = 16
12 years ago
Shubh
16
12 years ago

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