Question
prove that tanA divided by the sinA equals the secA
Answers
Reiny
tanA = sinA/cosA
so tanA / sinA
= (sinA/cosA)/sinA
= 1/cosA
= secA
so tanA / sinA
= (sinA/cosA)/sinA
= 1/cosA
= secA
NIKITA
(sinA/cosA)/ sinA
= 1/cosA
= secA
= 1/cosA
= secA