Question
A vertical wall (5.3 m multiplied by 2.3 m) in a house faces due east. A uniform electric field has a magnitude of 157 N/C. This field is parallel to the ground and points 38° north of east. What is the electric flux through the wall?
Answers
drwls
The E-field lines make an angle of 38 degrees with the normal to the wall. The flux is the E-field magnitude multiplied by wall area and cos 38.
E-Flux = 157*5.3*2.3*0.788
= 1508 N*m^2/C
E-Flux = 157*5.3*2.3*0.788
= 1508 N*m^2/C