Asked by Sarah H
A liquid is heated from 33.96°C to 104.32°C. The vapor pressure increases from 23.54torr to 984.35torr. What is the heat of vaporization of the liquid in kJ/mol?
The change in temperature is 70.36°C.
Change in vapor pressure = 960.76 torr.
What is the equation to find the heat of vaporization given that we know the change in pressure, and change in temperature?
The change in temperature is 70.36°C.
Change in vapor pressure = 960.76 torr.
What is the equation to find the heat of vaporization given that we know the change in pressure, and change in temperature?
Answers
Answered by
DrBob222
Isn't that the Clausius-Clapeyron equation?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.