Asked by helpless

Let f:{0,1}^3→{0,1} with f(101)=1 and f(x)=0 for x≠101. In this question, we will run through two iterations of the algorithm.

(a) What is the superposition after the initialization step? Note that you can describe the superposition ∑x∈{0,1}3αx|x> by specifying two numbers α101 and αx for x≠101.
Answer in this format: α101: αx for x≠101:

(b) After the phase inversion in iteration 1?
Answer in this format: α101: αx for x≠101:

(c) After the inversion about mean in iteration 1?
Answer in this format: α101: αx for x≠101:

(d) After the phase inversion in iteration 2?
Answer in this format: α101: αx for x≠101:

(e) After the inversion about mean in iteration 2?
Answer in this format: α101: αx for x≠101:

Answers

Answered by My
Anyone please!
Answered by Anonymous
1/sqrt(8),1/sqrt(8)
-1/sqrt(8),1/sqrt(8)
5/(2*sqrt(8)),1/(2*sqrt(8))
-5/(2*sqrt(8)),1/(2*sqrt(8))
11/(4*sqrt(8)),-1/(4*sqrt(8))
Answered by chepe
problem 6 plz
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