an open topped cylinder has a volume of 125 cubic inches. determine the radius of the pot that will minimize it's surface area.

What I have so far...

radius =r

keight =h

V=πr²h

125/πr²=h

SA = πr² + 2πr(h)

= πr² + 2πr(125/πr²)

SA =πr² +250/r

2 answers

so far so good:

A = pi r^2 + 250/r
dA/dr = 2pi r - 250/r^2
so, when is dA/dr = 0?
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