Question

A particle wavelength (λp) of a proton is 10-12m.
What is the velocity of this proton [m/s]?

To achieved the velocity that you just computed, what must have been the potential difference (V) through which the proton was accelerated?

An electron of wavelength 1.74*10-10m strikes an atom of ionized helium (He+). What is the wavelength (m) of the light corresponding to the line in the emission spectrum with the smallest energy transition?

Answer 1

a) 3.96148749852*10^5
b) 820
c)....?

Answer 2

Thanks dear but actually I got the two first ones last night and stuck with part c. :(

Answer 3

Anyone for c) please?

Answer 4

what about some brainstorming???do we have to use Rydberg's equation??

Answer 5

What about doing your own work and not trying to cheat?

Answer 6

Please stop spamming.