1.25 pounds x 453.6 g/pound = ?grams
?grams x 10.85 kcal/g = x kcal
x kcal x 1000 cal/kcal = 120,000 g H2O x specific heat H2O (cal/g) x (Tfinal-Tinitial)
The amount of energy released by burning a fuel source, measured in energy per mass, is called the fuel value. If all the energy obtained from burning 1.25 pounds of butane (fuel value is 10.85 kcal/g) is used to heat 120.0 kg of water at an initial temperature of 21.2 °C, what is the final temperature?
2 answers
DrBob,
started to do this equation, but am unsure if degrees Celcius needs to be converted to Kelvins in this instance before proceeding with the problem. Does it need to be converted, or is that just for calculation in Gas Laws?
started to do this equation, but am unsure if degrees Celcius needs to be converted to Kelvins in this instance before proceeding with the problem. Does it need to be converted, or is that just for calculation in Gas Laws?
0 answers