Question
Find dy/dx.
7xy^3 − x^2y = 6
7xy^3 − x^2y = 6
Answers
bobpursley
Newtons method:
7x(3y^2)dy+7y^3dx-2xydx-x^2 dy=0
dy/dx(21xy^2-x^2)=2xy-7y^2
dy/dx= you do the fraction.
7x(3y^2)dy+7y^3dx-2xydx-x^2 dy=0
dy/dx(21xy^2-x^2)=2xy-7y^2
dy/dx= you do the fraction.