Question
Find dy/dx.
y^3 = 8x^3 + 4x
y^3 = 8x^3 + 4x
Answers
bobpursley
3y^2 dy=24x^2 dx + 4dx
dy/dx=(8x^2+1)/(y^2) check that
dy/dx=(8x^2+1)/(y^2) check that
Reiny
bob probably meant to type
dy/dx = (8x^2 + 4/3)/(y^2)
dy/dx = (8x^2 + 4/3)/(y^2)