Asked by Mary Ann
Calculate the pOH of an aqueous solution of 146.6 ml of 0.000625 M HBr(aq) after dilution to 850 ml.
Answers
Answered by
DrBob222
(HBr) diluted = 0.000625 x (146.6/860) = about 1.08E-4
pH = -log(H^+) = -log(HBr) since HBr is a strong acid and ionizes 100%.
Then pH + pOH = pKw = 14. You know pH and pKw solve for pOH.
pH = -log(H^+) = -log(HBr) since HBr is a strong acid and ionizes 100%.
Then pH + pOH = pKw = 14. You know pH and pKw solve for pOH.
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