Asked by Tonya
A layer of oil (n = 1.45) floats on an unknown liquid. A ray of light originates in the oil and passes into the unknown liquid. The angle of incidence is 64.8 degrees, and the angle of refraction is 68.0 degrees. What is the index of refraction of the unknown liquid?
Answers
Answered by
Elena
sini/sinr=n2/n1
n2=n1(sini/sinr)=1.45(sin64.8/sin68.0)=...
n2=n1(sini/sinr)=1.45(sin64.8/sin68.0)=...
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