Asked by qwerty
- What is QFT6 of 1/√2(|0> + |3>?
- What is QFT6 of 1/√2(|1> + |4>?
- What is QFT6 of 1/√3(|0> + |2> + |4>?
- What is QFT6 of 1/√3(|1> + |3> + |5>?
- What is QFT6 of 1/√2(|1> + |4>?
- What is QFT6 of 1/√3(|0> + |2> + |4>?
- What is QFT6 of 1/√3(|1> + |3> + |5>?
Answers
Answered by
Help
What is w? You can use e, pi, and M in your response. Please do not subtitute 6 for M.
Answered by
Count Iblis
You need to tell us how the operator QFT6 is defined. E.g. how does QFT6 act on the basis states |n> ?
Answered by
Help
In Problems 1 to 5 we will work through example of QFTM for M = 6.
Problem 1:
What is w? You can use e, pi, and M in your response. Please do not subtitute 6 for M.
Specify the probability amplitudes. You should use w to denote ƒÖ, but please fully simplify your answer such that you only use ƒÖ and ƒÖ2 and no higher-degree terms.
Problem 2:
What is QFT6 of 1/ã2(|0> + |3>?
Problem 3:
What is QFT6 of 1/ã2(|1> + |4>?
Problem 4:
What is QFT6 of 1/ã3(|0> + |2> + |4>?
Problem 5:
What is QFT6 of 1/ã3(|1> + |3> + |5>?
Problem 1:
What is w? You can use e, pi, and M in your response. Please do not subtitute 6 for M.
Specify the probability amplitudes. You should use w to denote ƒÖ, but please fully simplify your answer such that you only use ƒÖ and ƒÖ2 and no higher-degree terms.
Problem 2:
What is QFT6 of 1/ã2(|0> + |3>?
Problem 3:
What is QFT6 of 1/ã2(|1> + |4>?
Problem 4:
What is QFT6 of 1/ã3(|0> + |2> + |4>?
Problem 5:
What is QFT6 of 1/ã3(|1> + |3> + |5>?
Answered by
Hal
In Problems 1 to 5 we will work through example of QFTM for M = 6.
Problem 1:
What is w? You can use e, pi, and M in your response. Please do not subtitute 6 for M.
Specify the probability amplitudes. You should use w to denote w, but please fully simplify your answer such that you only use w and w^2 and no higher-degree terms.
Problem 2:
What is QFT6 of 1/ã2(|0> + |3>?
Problem 3:
What is QFT6 of 1/ã2(|1> + |4>?
Problem 4:
What is QFT6 of 1/ã3(|0> + |2> + |4>?
Problem 5:
What is QFT6 of 1/ã3(|1> + |3> + |5>?
Problem 1:
What is w? You can use e, pi, and M in your response. Please do not subtitute 6 for M.
Specify the probability amplitudes. You should use w to denote w, but please fully simplify your answer such that you only use w and w^2 and no higher-degree terms.
Problem 2:
What is QFT6 of 1/ã2(|0> + |3>?
Problem 3:
What is QFT6 of 1/ã2(|1> + |4>?
Problem 4:
What is QFT6 of 1/ã3(|0> + |2> + |4>?
Problem 5:
What is QFT6 of 1/ã3(|1> + |3> + |5>?
Answered by
Help
What is w? You can use e, pi, and M in your response. Please do not subtitute 6 for M.
Got this result for above question but it is graded wrong, can someone help?
e^i*pi/3
Got this result for above question but it is graded wrong, can someone help?
e^i*pi/3
Answered by
Anonymous
e^((2*pi*i)/M)
Answered by
Help
Thank you!
Did somebody figure out one or all of the QTF6 questions?
Did somebody figure out one or all of the QTF6 questions?
Answered by
helpman
Problem 2:
1/sqrt(3),0,1/sqrt(3),0,1/sqrt(3),0
1/sqrt(3),0,1/sqrt(3),0,1/sqrt(3),0
Answered by
Gyanno
In this problem, we will carry out some steps of the quantum factoring algorithm for N = 15
(a) What is the period k of the periodic superposition set up by the quantum factoring algorithm if it chooses x = 2 ?
(b) Assume that we found this k using period finding algorithm. Use k to find a non-trivial square root of 1(mod 15) . Write your answer as an integer between 0 and 15.
(c) Then, the algorithm proceeds by computing gcd (x,y) for some integers x and y . List these two numbers separated by a comma.
If there are more than one correct solution, provide any one of them.
(a) What is the period k of the periodic superposition set up by the quantum factoring algorithm if it chooses x = 2 ?
(b) Assume that we found this k using period finding algorithm. Use k to find a non-trivial square root of 1(mod 15) . Write your answer as an integer between 0 and 15.
(c) Then, the algorithm proceeds by computing gcd (x,y) for some integers x and y . List these two numbers separated by a comma.
If there are more than one correct solution, provide any one of them.
Answered by
Help
Thanks Anonymous and Gyanno!
Anyone got Problem 3, 4 or 5?
Answered by
Help
Meant thanks Helpman!
Answered by
Argon
yes, anyone for problems 3-5?
Answered by
Matur
Has anyone figured out problem 3, 4 or 5 please?
Answered by
helpman
Problem 4:
1/sqrt2 , 0 , 0 , 1/sqrt2 , 0 , 0
1/sqrt2 , 0 , 0 , 1/sqrt2 , 0 , 0
Answered by
helpman
(a) k=4
(b) 4
(c)3,15 or 5,15
(b) 4
(c)3,15 or 5,15
Answered by
Anne
Problems 6 and 7 please!
Answered by
gluck
7.
a) 5 prep
b) 1/sqrt(k)
c) 0
a) 5 prep
b) 1/sqrt(k)
c) 0
Answered by
Gyanno
thank you!!
Answered by
helpman
Problems 6
β′j=e^(2*pi*i*j/M)
β′j=e^(2*pi*i*j/M)
Answered by
Anne
Anyone have finished problems 3 and 5?
Gluck and helpman, thanks so much, very usefull for me!
Gluck and helpman, thanks so much, very usefull for me!
Answered by
helpman
no probleme u welcome
Answered by
gluck
3)
1/sqrt(3), 0,(w^2)/sqrt(3), 0,
(-w)/(sqrt(3), 0.
5)1/sqrt(2), 0, 0, -1/sqrt(2) , 0,0
1/sqrt(3), 0,(w^2)/sqrt(3), 0,
(-w)/(sqrt(3), 0.
5)1/sqrt(2), 0, 0, -1/sqrt(2) , 0,0
Answered by
Anonymous
Thanks Gluck
Answered by
Anne
Thanks so much!
Answered by
Anon
Please help for Q9!
Answered by
rare
please ans 9 and 10
Answered by
simi
can anyone plz tell me ans 9..i am stuck with it..and my ans is coming wrong continously
Answered by
boss
number 9 anyone!!
Answered by
Vassilis
Problem 9 N=15
a)4 b)4 c)3.15 or 5.15 (gcd(x+1,15) or gcd(x-1,15))
a)4 b)4 c)3.15 or 5.15 (gcd(x+1,15) or gcd(x-1,15))
Answered by
Vassilis
Problem 9 N=21
a)6 b)8
a)6 b)8
Answered by
noname
answer 10 : option no. 2 & 4
Answered by
noname
your solution for problem 3 & 5 is not correct. please tell me correct answer
Answered by
noname
what is the solution of problem 9. please answer fast
Answered by
Anonymous
p9: a)6 b)8 c) 7,21
what about problem 3?
what about problem 3?
Answered by
noname
dont know...anyone know then tell about problem 3 & 5
Answered by
random
please anyone post answer of problm 3 & 5. please make it fast
Answered by
Anonymous
p3: 1/sqrt(3);0;2*w^2/sqrt(12);0;-2*w/sqrt(12);0
p5: 1/sqrt(2);0;0;-1/sqrt(2);0;0
p5: 1/sqrt(2);0;0;-1/sqrt(2);0;0
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