Asked by qwerty

- What is QFT6 of 1/√2(|0> + |3>?

- What is QFT6 of 1/√2(|1> + |4>?

- What is QFT6 of 1/√3(|0> + |2> + |4>?

- What is QFT6 of 1/√3(|1> + |3> + |5>?

Answers

Answered by Help
What is w? You can use e, pi, and M in your response. Please do not subtitute 6 for M.
Answered by Count Iblis
You need to tell us how the operator QFT6 is defined. E.g. how does QFT6 act on the basis states |n> ?
Answered by Help
In Problems 1 to 5 we will work through example of QFTM for M = 6.

Problem 1:
What is w? You can use e, pi, and M in your response. Please do not subtitute 6 for M.


Specify the probability amplitudes. You should use w to denote ƒÖ, but please fully simplify your answer such that you only use ƒÖ and ƒÖ2 and no higher-degree terms.

Problem 2:
What is QFT6 of 1/ã2(|0> + |3>?

Problem 3:
What is QFT6 of 1/ã2(|1> + |4>?

Problem 4:
What is QFT6 of 1/ã3(|0> + |2> + |4>?

Problem 5:
What is QFT6 of 1/ã3(|1> + |3> + |5>?
Answered by Hal
In Problems 1 to 5 we will work through example of QFTM for M = 6.

Problem 1:
What is w? You can use e, pi, and M in your response. Please do not subtitute 6 for M.


Specify the probability amplitudes. You should use w to denote w, but please fully simplify your answer such that you only use w and w^2 and no higher-degree terms.

Problem 2:
What is QFT6 of 1/ã2(|0> + |3>?

Problem 3:
What is QFT6 of 1/ã2(|1> + |4>?

Problem 4:
What is QFT6 of 1/ã3(|0> + |2> + |4>?

Problem 5:
What is QFT6 of 1/ã3(|1> + |3> + |5>?
Answered by Help
What is w? You can use e, pi, and M in your response. Please do not subtitute 6 for M.
Got this result for above question but it is graded wrong, can someone help?

e^i*pi/3
Answered by Anonymous
e^((2*pi*i)/M)
Answered by Help
Thank you!

Did somebody figure out one or all of the QTF6 questions?
Answered by helpman
Problem 2:
1/sqrt(3),0,1/sqrt(3),0,1/sqrt(3),0
Answered by Gyanno
In this problem, we will carry out some steps of the quantum factoring algorithm for N = 15
(a) What is the period k of the periodic superposition set up by the quantum factoring algorithm if it chooses x = 2 ?
(b) Assume that we found this k using period finding algorithm. Use k to find a non-trivial square root of 1(mod 15) . Write your answer as an integer between 0 and 15.
(c) Then, the algorithm proceeds by computing gcd (x,y) for some integers x and y . List these two numbers separated by a comma.

If there are more than one correct solution, provide any one of them.
Answered by Help


Thanks Anonymous and Gyanno!

Anyone got Problem 3, 4 or 5?
Answered by Help
Meant thanks Helpman!
Answered by Argon
yes, anyone for problems 3-5?
Answered by Matur
Has anyone figured out problem 3, 4 or 5 please?
Answered by helpman
Problem 4:

1/sqrt2 , 0 , 0 , 1/sqrt2 , 0 , 0
Answered by helpman
(a) k=4
(b) 4
(c)3,15 or 5,15
Answered by Anne
Problems 6 and 7 please!
Answered by gluck
7.
a) 5 prep
b) 1/sqrt(k)
c) 0
Answered by Gyanno
thank you!!
Answered by helpman
Problems 6


β′j=e^(2*pi*i*j/M)
Answered by Anne
Anyone have finished problems 3 and 5?

Gluck and helpman, thanks so much, very usefull for me!
Answered by helpman
no probleme u welcome
Answered by gluck
3)
1/sqrt(3), 0,(w^2)/sqrt(3), 0,
(-w)/(sqrt(3), 0.

5)1/sqrt(2), 0, 0, -1/sqrt(2) , 0,0
Answered by Anonymous
Thanks Gluck
Answered by Anne
Thanks so much!
Answered by Anon
Please help for Q9!
Answered by rare
please ans 9 and 10
Answered by simi
can anyone plz tell me ans 9..i am stuck with it..and my ans is coming wrong continously
Answered by boss
number 9 anyone!!
Answered by Vassilis
Problem 9 N=15
a)4 b)4 c)3.15 or 5.15 (gcd(x+1,15) or gcd(x-1,15))
Answered by Vassilis
Problem 9 N=21
a)6 b)8
Answered by noname
answer 10 : option no. 2 & 4
Answered by noname
your solution for problem 3 & 5 is not correct. please tell me correct answer
Answered by noname
what is the solution of problem 9. please answer fast
Answered by Anonymous
p9: a)6 b)8 c) 7,21

what about problem 3?
Answered by noname
dont know...anyone know then tell about problem 3 & 5
Answered by random
please anyone post answer of problm 3 & 5. please make it fast
Answered by Anonymous
p3: 1/sqrt(3);0;2*w^2/sqrt(12);0;-2*w/sqrt(12);0

p5: 1/sqrt(2);0;0;-1/sqrt(2);0;0
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