Asked by Alice
Does anyone know how to find the derivative of 3x^ln(2x)?
Answers
Answered by
bobpursley
d/dx f(x)<sup>g(x)</sup> =
f(x)<sup>g(x)</sup>* [g'(x)ln(f(x))+g(x)f'(x)/f(x) ]
Answered by
Count Iblis
3x^ln(2x) =
3 exp[ln(2x) ln(x)]
The derivative of exp(f(x)) is
exp(f(x)) f'(x)
You can easily prove this using the chain rule.
3 exp[ln(2x) ln(x)]
The derivative of exp(f(x)) is
exp(f(x)) f'(x)
You can easily prove this using the chain rule.
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