from the vertex, we know that
y = a(x-2)^2 - 1
since y(3) = 1,
1 = a(3-2)^2-1
1 = a-1
a = 2
y = 2(x-2)^2 - 1
Determine the quadratic function of f whose vertex is (2,-1) and passes through (3,1)
f(x)=
1 answer
f(x)=
1 answer