Asked by Updesh Shah
a man wishes to swin across a river 600 m wide. If can swim at the rate of 4 km/hr in still water and the river flows at 2 km/hr. Then in what direction must he swim to reach a point exactly opposite to the starting point bnd when will he reach it ?
Answers
Answered by
drwls
His velocity relative to water must have a 2 km/hr component upstream. The component across the stream is therefore
sqrt[4^2 - 2^2) = 3.464 km/hr
He must swim at an angle arcsin(2/4) = 30 degrees relative to straight-across.
The time to swim across will be
T = 0.6/3.464 = 0.1732 hr = 10.4 minutes
sqrt[4^2 - 2^2) = 3.464 km/hr
He must swim at an angle arcsin(2/4) = 30 degrees relative to straight-across.
The time to swim across will be
T = 0.6/3.464 = 0.1732 hr = 10.4 minutes
Answered by
Silash
Can u show the figure of it?
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