OK, here is how to do that:
How fast was the coin going after 1 second? V(1) = 1*t = 9.8 m/s
After 2 seconds? V(2) = 2*t = 19.6 m/s
How fast was the coin going when it hit the water? V(T) = 5*T
Let T be the time when it hit the water.
It will also take the sound of the splash 340*T to be heard. 340 m/s is the assumed speed of sound.
How far down is the water?
Let H be the depth of the water in the well.
sqrt(2H/g) + H/340 = 5
You will have to solve that graphically, by iteration or the quadratic formula
H = 108 meters
Time when it hit water:
T = sqrt(2H/g) = 4.69 s
V(4.69) = 46 m/s
If a girl drops a coin into a wishing well. After exactly 5 seconds she hears it splash into the water. How fast was the coin going after 1 second? After 2 seconds? How fast was the coin going when it hit the water? How far down is the water? Could you please help with the formulas and the answers for these questions?
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