a bag contains lettered tiles, two for each letter of the alphabet. What is the probability of drawing a tile with the letter A? express the probability ratio as a fraction and as a decimal rounded to the nearest hundredth

1/52 = 0.01923 = 0.02

since there are 2 A,s would the probablitiy be 2/52 = 1/26?

Oops! Thanks! You caught my mistake

Yes, it would be 1/26 = 0.03846 = 0.04

Thank you for the help Ms Sue you put me on the right track to figure out the question

You're very welcome. Sorry about my goof -- but I'm glad you understand now.

There are 100 lettered tiles in a board game. You chose the following tiles without looking: B, E, M, Z, R, U, T, S.

How many of the 100 tiles would you expect to be vowels?

To calculate the probability of drawing a tile with the letter A, we need to know the total number of tiles in the bag and the number of tiles with the letter A.

Since there are two tiles for each letter of the alphabet, there are a total of 2 * 26 = 52 tiles in the bag.

Since we are interested in the probability of drawing a tile with the letter A, we need to find out how many tiles have the letter A. Since each letter has two tiles, there are 2 tiles with the letter A.

Therefore, the probability of drawing a tile with the letter A can be calculated by dividing the number of tiles with the letter A by the total number of tiles in the bag:

Probability = (Number of tiles with the letter A) / (Total number of tiles)
= 2 / 52

To express the probability as a fraction, we simplify the fraction if possible:
Probability = 1 / 26

To express the probability as a decimal rounded to the nearest hundredth, we divide 1 by 26:
Probability ≈ 0.04

Hence, the probability of drawing a tile with the letter A is 1/26 as a fraction and approximately 0.04 as a decimal rounded to the nearest hundredth.