Ask a New Question

Asked by Cody

How many drops (1 drop=0.05mL) of 0.20M KI must we add to 100.0 mL of 0.010M Pb(NO3)2 to get a precipitate of lead iodide to start. Ksp of PbI2=7.1e-9.
Answer=9 drops. Please show steps.
12 years ago

Answers

There are no human answers yet.
There are no AI answers yet. The ability to request AI answers is coming soon!

Submit Your Answer


We prioritize human answers over AI answers.

If you are human, and you can answer this question, please submit your answer.

Related Questions

you add 0.05ml of 0.10M agno3 to 4ml of 2.0 nacl it forms saturated solution of agcl<---> ag+ + cl-... If 5.05mL of 0.1000 M NaOH solution is needed to just neutralize excess acid after 20.00 mL of HCl w... 1. You need eye drops for your dry eyes. You brought only a few dollars with you to the store. Whic... If there are 35 drops in 1 mL, how many microliters are there per drop? If ten drops of 0.3 M HCl are mixed with ten drops of 0.3 M Na2S2O3, what will be the concentration... You need eye drops for your dry eyes. You brought only a few dollars with you to the store. Which is... 5 drops 1) How many drops of 12M HCl would you add to 1.00 L of 0.100 M HC2H3O2 to make [C2H3O2-] = 1.0 x 10... 10.0 mL of HCl and a few drops of phenolphthalein indicator. The buret contains 0.110 M NaOH. Wha... A 4.0 kg mud ball drops from rest at a height of 12 m. If the impact between the ball and the ground...
Submit Your Answer

Question

How many drops (1 drop=0.05mL) of 0.20M KI must we add to 100.0 mL of 0.010M Pb(NO3)2 to get a precipitate of lead iodide to start. Ksp of PbI2=7.1e-9.
Answer=9 drops. Please show steps.

Ask a New Question
Archives Contact Us Privacy Policy Terms of Use