3x+6 over 4x+12 divided by x^2-4 over x+3

2 answers

3x+6 over 4x+12 divided by x^2-4 over x+3
= 3(x+2)/(4(x+3) ) ÷ [(x+2)(x-2)/(x+3)]
= 3(x+2)/(4(x+3)) [ (x+3)/(x+2)(x-2) ]
= 3/(4(x-2) ) , x ≠ +3, ± 2
Right triangle - find length of the missing side. A=16 is the base; B=63 is the side. What is the length of C?
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