Asked by po
A skier is going down a hill with a coefficient of friction of 0.21 and an angle of 7.5 degrees. if the skier has an initial velocity of 30 m/s, how fast will she be going after 10 s
Answers
Answered by
bobpursley
vf=vi+at
but a= netforce/mass
a= (mg*cosTheta-mg*mu*sinTheta)/m
a= g(cosTheta-mu*sinTheta
solve for vf.
but a= netforce/mass
a= (mg*cosTheta-mg*mu*sinTheta)/m
a= g(cosTheta-mu*sinTheta
solve for vf.
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