Asked by Hasane
exponent law question:
Simplify the following exponents.
1. (16)(2^(x+2))
2. ((ab)^(2x+y))/(a^(x)b^(y))
Simplify the following exponents.
1. (16)(2^(x+2))
2. ((ab)^(2x+y))/(a^(x)b^(y))
Answers
Answered by
Reiny
(16)(2^(x+2))
= (2^4) (2^(x+2) )
= 2^(x+6)
((ab)^(2x+y))/(a^(x)b^(y))
= a^(2x+y) b^(2x+y) / ( (a^x)(b^y) )
= a^(x+y) b^(2x)
= (2^4) (2^(x+2) )
= 2^(x+6)
((ab)^(2x+y))/(a^(x)b^(y))
= a^(2x+y) b^(2x+y) / ( (a^x)(b^y) )
= a^(x+y) b^(2x)
Answered by
Hasane
Wouldn't there be a 4 attached to the x for the first one?
Answered by
Reiny
no, you add the exponents and
4 + x+2 = x+6
4 + x+2 = x+6
Answered by
Hasane
Hm ok. If I had (x^(a-b))^a+b
..would that be multiplication or adding of the a's and b's
..would that be multiplication or adding of the a's and b's
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